[tex]3^{-2}+2^{-1}=\big(\frac{1}{3}\big)^2+\big(\frac{1}{2}\big)^1=\frac{1}{9} +\frac{1}{2} =\frac{2}{18} +\frac{9}{18} =\frac{2+9}{18} =\frac{11}{18}[/tex]
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[tex]3^{-2}+2^{1}=\big(\frac{1}{3}\big)^2+2=\frac{1}{9} +2 =\frac{1}{9} +\frac{18}{9} =\frac{1+18}{9} =\frac{19}{9}[/tex]
