Resposta:
[tex] \Delta = {b}^{2} - 4ac \\ \\ {x}^{2} + 3x - 10 = 0 \\ \\ a = 1 \: \: b = 3 \: \: c = - 10 \\ \\ Bhaskara \\ \\ \dfrac{ -b \pm \sqrt{ \Delta} }{2a} \\ \\ \dfrac{ - 3 \pm \sqrt{ {3}^{2} - 4(1)( - 10)} }{2(1)} \\ \\ \dfrac{ - 3 \pm \sqrt{9 + 40} }{2} \\ \\ \dfrac{ - 3 \pm \sqrt{49} }{2} \\ \\ x = \dfrac{ - 3 + 7}{2} \\ \\ x \: = \dfrac{4}{2} \\ \\ \purple{x = 2} \\ \\ x = \dfrac{ - 3 - 7}{2} \\ \\ x = \dfrac{ - 10}{2} \\ \\ \purple{x = - 5} \\ \\ [/tex]
Letra a)
Bons Estudos!
