Resposta: X=-5 e X=-7
(X+5) (X+7)=0
[tex]X^{2}[/tex]+7x+5x+25=0
[tex]x^{2}[/tex]+12x+35=0
Separar A,B,C:
A=1
B=12
C=35
ΔDelta:
Δ=[tex]b^{2}[/tex]-4.a.c
Δ=[tex]12^{2}[/tex]-4.1.35
Δ=144-140
Δ=4
Bhaskara:
[tex]x=\frac{-b+-\sqrt{delta} }{2.a}[/tex]
[tex]x=\frac{-12+-\sqrt{4}}2[/tex]
[tex]x^{1}=\frac{-12+2}{2}[/tex] [tex]x^{1}=\frac{-10}{2}[/tex] [tex]x^{1}=\frac{-5}{2}[/tex]
[tex]x^{2} =\frac{-12-12}{2}[/tex] [tex]x^{2} = \frac{-14}{2\\}[/tex] [tex]x^{2} =-7[/tex]
Espero ter ajudado:)
