caucule o valor de x
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Aplicamos o Teorema de Tales para resolver:
[tex]\frac{2x-1}{3x+1} =\frac{4}{7}[/tex]
[tex]7(2x-1)=4(3x+1)[/tex]
[tex]14x-7=12x+4[/tex]
[tex]14x-12x=4+7[/tex]
[tex]2x=11[/tex]
[tex]x=\frac{11}{2}[/tex]