A energia potencial elástica será igual a energia potencial gravitacional, portanto:
Efel=Epg
[tex] \frac{k \times {x}^{2} }{2} = m \times g \times h[/tex]
[tex] \frac{1000 \times {(0.5)}^{2} }{2} = 2 \times 10 \times h[/tex]
[tex]125 = 20 \times h[/tex]
[tex]h = 6.25m[/tex]
