[tex]\displaystyle resultado=\frac{2^{-3}+3^{-1}}{2^0+2^1+(\frac{1}{2})^{-3}}\\\\\\resultado=\frac{\frac{1}{2^3}+\frac{1}{3^1}}{1+2+\frac{2^3}{1^3}}\\\\\\resultado=\frac{\frac{1}{8}+\frac{1}{3}}{3+\frac{8}{1}}\\\\\\resultado=\frac{\frac{1}{8}+\frac{1}{3}}{3+8}\\\\\\resultado=\frac{\frac{1}{8}+\frac{1}{3}}{11}\\\\\\resultado=\frac{\frac{3+8}{24}}{11}\\\\\\resultado=\frac{\frac{11}{24}}{11}\\\\\\resultado=\frac{11}{24}.\frac{1}{11}\\\\\\resultado=\frac{1}{24}[/tex]
